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公差,這兩種標注,表示意義有什么區(qū)別的?

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1#
發(fā)表于 2014-5-23 20:05:11 | 只看該作者 回帖獎勵 |倒序瀏覽 |閱讀模式
這兩種標注,表示意義有什么區(qū)別的?

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2#
發(fā)表于 2014-5-23 20:19:55 | 只看該作者
本帖最后由 HC小丁 于 2014-5-23 20:22 編輯
4 T# ]9 t5 F" A
+ Y7 d; _; D, c9 }- R( C8 g基本尺寸不一樣,實際加工尺寸可能是一樣的,但設計尺寸不同
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3#
發(fā)表于 2014-5-23 20:57:54 | 只看該作者
前一種標法,尺寸兩側(cè)分別加工成型,如銑或磨削兩個側(cè)面;后一種標法一般用于一個刀具完成的加工成型,如鉆孔,砂輪磨槽。
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4#
發(fā)表于 2014-5-23 21:00:35 | 只看該作者
對于我們加工的來說:左圖我們會盡量把尺寸做到20.45至20.5之間
( I; Y( J' ^$ S                              右圖我們會盡量把尺寸做到20.4至20.45之間7 w" Q2 |8 M: j& c- ]$ F: ?+ O
                便于裝配
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5#
發(fā)表于 2014-5-23 22:20:44 | 只看該作者
是不是根據(jù)入體原則來的?
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6#
發(fā)表于 2014-5-23 22:56:22 | 只看該作者
長見識了,我原先以為是個人的習慣問題,
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7#
發(fā)表于 2014-5-24 10:31:03 | 只看該作者
一般是另一個部件的基本尺寸一樣的
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8#
發(fā)表于 2014-5-26 23:12:49 | 只看該作者
9.2.3 Converting Dimensions to Equal Bilateral Tolerances
; }8 n4 b* u  ]6 E/ [
In Fig. 9-2, there were several dimensions that were toleranced using unilateral tolerances/ i9 U' m. k' l' V% M6 g
(such as .375 +.000/-.031,  3.019 +.012/-.000 and .438 +.000/-.015) or unequal bilateral tolerances (such0 n, f7 P) B: g$ A! a
as +1.500 +.010/-.004 ). If we look at the length of the shaft, we see that there are several different ways we
; d' N4 ]" M9 |0 B) W7 t. b# Dcould have applied the tolerances. Fig. 9-4 shows several ways we can dimension and tolerance the length; G- t& }0 s/ W* |# \. U
of the shaft to achieve the same upper and lower tolerance limits (3.031/3.019). From a design perspective,
2 h! T: p' `9 kall of these methods perform the same function. They give a boundary within which the dimension is
+ H) Q8 h) b0 u8 i! g6 |) Oacceptable.
6 k9 P% a% G' A+ B4 c$ M' Z, s6 g7 x3 ]# w" Q7 H  Y
The designer might think that changing the nominal dimension has an effect on the assembly. For
4 r8 @8 F5 u  Z. @! [# Jexample, a designer may dimension the part length as 3.019 +.012/-.000. In doing so, the designer may
$ w* y; y/ h+ f  b) z  Yfalsely think that this will help minimize the gap for Requirement 1. A drawing, however, doesn’t give
/ R7 y* y0 n# C9 o6 l1 K& _preference to any dimension within the tolerance range.
) B' l- Z- ?% _$ O8 ~; [9 Q* NFig. 9-5 shows what happens to the manufacturing yield if the manufacturer “aims” for the dimension
5 C. @8 D6 z1 M, dstated on the drawing and the process follows the normal distribution. In this example, if the manufacturer0 P6 S2 i5 V$ J! i$ n9 f
aimed for 3.019, half of the parts would be outside of the tolerance zone. Since manufacturing shops want1 c0 W& u9 C$ h& l
to maximize the yield of each dimension, they will aim for the nominal that yields the largest number of
. o: \* e% a9 A& }5 k0 dgood parts. This helps them minimize their costs. In this example, the manufacturer would aim for 3.025.' k$ v# E4 H, v" d' w% I0 U0 C
This allows them the highest probability of making good parts. If they aimed for 3.019 or 3.031, half of the
4 L2 _2 x" j% F3 e- i# r; Wmanufactured parts would be outside the tolerance limits.
1 n# m; F, B; i7 _% m5 XAs in the previous example, many manufacturing processes are normally distributed. Therefore, if we
6 ]! ~3 A1 t9 j; Xput any unilateral, or unequal bilateral tolerances on dimensions, the manufacturer would convert them to
+ _$ Q. |" \4 Fa mean dimension with an equal bilateral tolerance. The steps for converting to an equal bilateral tolerance* T6 z8 d( H" [
follow.; r8 Y9 f" ~2 h# t9 S" G% h2 e

& m- H' D9 R5 ~& U) f/ F. B* Q
  z" p) c) w# [1 K7 u4 R6 r1. Convert the dimension with tolerances to an upper limit and a lower limit. (For example, 3.028 +.003/* A( l8 y: _. k3 s5 ?: H
-.009 has an upper limit of 3.031 and a lower limit of 3.019.)
+ k2 j: l) F; I0 u4 d& d' d2. Subtract the lower limit from the upper limit to get the total tolerance band. (3.031-3.019=.012)
6 I6 k. Y! R4 M& c3. Divide the tolerance band by two to get an equal bilateral tolerance. (.012/2=.006)
$ v5 y7 H+ O& G( g  t' z4. Add the equal bilateral tolerance to the lower limit to get the mean dimension. (3.019 +.006=3.025).
; Z3 v5 j: S) ^Alternately, you could subtract the equal bilateral tolerance from the upper limit. (3.031-.006=3.025)- b: o( W/ M# V- ?# ]
) T! H* n) a. c& r! o( y
As a rule, designers should use equal bilateral tolerances. Sometimes, using equal bilateral tolerances
# N6 a9 p0 a! ~3 ?8 M4 vmay force manufacturing to use nonstandard tools.  In these cases, we should not use equal bilateral0 Z5 J. P) O# u/ m1 M
tolerances.  For example, we would not want to convert a drilled hole diameter from Æ.125 +.005/-.001 to
5 ~: X. Z; h; u. [3 p' h2 e$ hÆ.127 ±.003. In this case, we want the manufacturer to use a standard Æ.125 drill. If the manufacturer sees5 J4 Q6 W( D5 u4 ~
Æ.127 on a drawing, he may think he needs to build a special tool. In the case of drilled holes, we would. y7 B8 E# C" g1 z) C
also want to use an unequal bilateral tolerance because the mean of the drilling process is usually larger
$ d+ x/ }# }' [$ ^than the standard drill size. These dimensions should have a larger plus tolerance than minus tolerance.
# g& J' s- B% u" ^: \# E7 v) G. U" ~8 qAs we will see later, when we convert dimensions to equal bilateral tolerances, we don’t need to keep( `' {2 D$ Y( P! {" N. [$ ?$ z( w9 Y! |
track of which tolerances are “positive” and which tolerances are “negative” because the positive toler-
6 S+ _* g. P1 Q. o5 p3 t! f9 Aances are equal to the negative tolerances. This makes the analysis easier. Table 9-1 converts the neces-6 q0 O1 t. L0 Q
sary dimensions and tolerances to mean dimensions with equal bilateral tolerances.5 |$ G, d, Z* s, Z+ K; P: x7 Y. d- o

- b; K/ o( p8 t/ O0 t
' ]+ W9 C& o, U0 ^"Dimensioning and Tolerancing Handbook, by Paul J. Drake, Jr."
" B. l) Z# L) k& u3 O5 F2 h0 q, p% i

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9-2表中的尺寸有的具有零位偏差,有的尺寸有正負偏差。若只看軸的尺寸,可見有多種標注公差的方式。 9-4表中,尺寸的上下偏差計算值相同,但是標注不同。從設計師角度看,結果一樣的。  發(fā)表于 2014-5-30 16:57
這么吊,英文啊  發(fā)表于 2014-5-29 20:44
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9#
發(fā)表于 2014-5-27 08:32:12 | 只看該作者
我來看看高手們怎么說,我對這些太不熟悉了,這幾天看書貌似看懂了,其實還是不懂
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10#
發(fā)表于 2014-5-27 16:02:09 | 只看該作者
左圖,尺寸盡量避開20.4
2 f- C  V. o( r8 z* \) O) S, b右圖,盡量把尺寸避開20.5

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恩,我也有這么個想法,但不知怎么講的,看你你說的頓時感覺就是這個意思  發(fā)表于 2014-5-29 20:45
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